Question 4
1 pts
The stopping distance d of an automobile is directly proportional to the square of its
speed s. On one road, a car requires 75 feet to stop from a speed of 30 miles per hour.
How many feet does the car require to stop from a speed of 48 miles per hour on the
same road?

The car requires 192 ft to stop from a speed of 48 mph

Explanation:

Given:

Speed, u = 30 mph

Stopping distance, d = 75 feet

The stopping distance d of a car after the brakes are applied varies directly as the square of the speed, u

So,

d = k (u)²

On substituting the value:

75 = k (30)²

k =

Speed, u₂ = 48 mph

d₂ = ?

d₂ = k (u₂)²

On substituting the values we get:

d₂ =

d₂ = 192 ft

answer: 177/8

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)