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The vagabonds were 220 miles apart at 2:00 am and were he...
Mathematics, 10.04.2020 17:57 katlynnschmolke
I REALLY NEED HELP ON HOW TO SOLVE!
The vagabonds were 220 miles apart at 2:00 am and were headed toward each other. if they met at 4:45 pm and one was traveling 20 miles per hour faster than the other, what was the speed of each vagabond?
Answers: 3
Mathematics, 21.06.2019 18:00
Since opening night, attendance at play a has increased steadily, while attendance at play b first rose and then fell. equations modeling the daily attendance y at each play are shown below, where x is the number of days since opening night. on what day(s) was the attendance the same at both plays? what was the attendance? play a: y = 8x + 191 play b: y = -x^2 + 26x + 126
Answers: 1
Mathematics, 21.06.2019 18:40
2people are trying different phones to see which one has the better talk time. chatlong has an average of 18 hours with a standard deviation of 2 hours and talk-a-lot has an average of 20 hours with a standard deviation of 3. the two people who tested their phones both got 20 hours of use on their phones. for the z-scores i got 1 for the chatlong company and 0 for talk-a-lot. what is the percentile for each z-score?
Answers: 1
Mathematics, 21.06.2019 18:50
The number of fish in a lake can be modeled by the exponential regression equation y=14.08 x 2.08^x where x represents the year
Answers: 3
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