Find the slope and y-intercept of the line that is parallel to y=-x-3and passes through the point (3,-2)
m=
b=

See a solution process below:
Explanation:
The equation in the problem is in slope-intercept form. The slope-intercept form of a linear equation is:
y
=
m
x
+
b

Where
m
is the slope and
b
is the y-intercept value.
y
=
−
1
x
+
3

Therefore, the slope of this line is:
−
1

The slope of parallel lines. Therefore, the slope of the line we are looking for is also
−
1
. We can substitute this into the slope-intercept formula giving:
y
=
−
1
x
b

Next, we can substitute the values from the point in the problem for
x
and
y
and solve for
b
:
5
=
(
−
1
⋅
3
)
+
b

5
=
−
3
+
b

3
+
5
=
3
−
3
+
b

8
=
0
+
b

8
=
b

Now, we can also substitute this into the formula to complete the equation:
y
=
−
1
x
+
8

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