On a separate sheet of paper, draw a unit circle. Use the drawing to complete the chart below that indicates the sign of the trigonometric functions in each quadrant.

In the box below, state the quadrant in which the following conditions are met:
a. The sine and tangent functions are both negative in this quadrant.
b. The cosine and cotangent functions are both negative in this quadrant.

36

step-by-step explanation:

step-by-step explanation:

fwms@lil_ben06

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15