How would you go about solving this with geometry?

Given:

From the figure, the sides are (2x + 5), (x + 12), (y - 4) and (x + 5)

The sides having lengths (2x + 5) and (x + 12) are equal.

The sides having lengths (y - 4) and (x + 5) are equal.

We need to solve the given figure.

Value of x:

Let us determine the value of x.

Equating the two sides having equal lengths (2x + 5) and (x + 12), we get;

Thus, the value of x is 7.

Value of y:

The value of y can be determined by equating the two sides (y - 4) and (x + 5) having equal lengths.

Thus, we have;

Substituting x = 7, we get;

Thus, the value of y is 16.

Side lengths of the figure:

The side lengths can be determined by substituting the values of x and y.

Thus, we have;

Thus, the lengths of the figure are 19, 19, 12, 12.

x = 7

y = 16

Step-by-step explanation:

2x + 5 = x + 12

x = 7

y - 4 = 7 + 5

y = 12 + 4

y = 16

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.