In a right △ABC, CD (D ∈ AB) is the angle bisector of the right ∠C. Two segments, DF (F ∈ AC) and DE (E ∈BC) are drawn parallel to the legs of the triangle. Prove that DFCE is a square.
m∠CED = 180° − m∠= by reason
m∠CFD = 180° − m∠= by reason

m∠CED = 180° − m∠ ECF = 90° by reason Same Side Interior Angles

m∠CFD = 180° −  m∠ ECF = 90° by reason Same Side Interior Angles

Step-by-step explanation:

You an see that they gave you parallel lines in DFCE. You can use these to input parallel line contingencies. You can then prove, using Same Side Interior  Angles, that angle CED and angle CFD are 90 degrees, making the shape a square as well. Hope this helped :)

complete the steps to find the area of the trapezoid.

area of rectangle = 256   square units

area of triangle 1 = 24  square units

area of triangle 2 = 16  square units

area of triangle 3 =   96 square units

area of trapezoid = 120  square units

step-by-step explanation:

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.