Find the 139th term of the arithmetic sequence whose first term is -28 and the common difference is 1/3

18

Step-by-step explanation:

The general formula for an arithmetic progression is a(n) = a(0) + d(n - 1), where a(0) is the first term,n is the index (counter), and d is the common difference between terms.

Here we have a(n) = -28 + (1/3)(n - 1)

and the 139th term is    a(139) = -28 + (1/3)(138)  =  -28 + 46 = 18

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions