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Mathematics, 10.04.2020 02:49 mirandac6775

\dfrac12(2a - 6b+ 8) = 2 1 (2a−6b+8)=start fraction, 1, divided by, 2, end fraction, left parenthesis, 2, a, minus, 6, b, plus, 8, right parenthesis, equals

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\dfrac12(2a - 6b+ 8) = 2 1 (2a−6b+8)=start fraction, 1, divided by, 2, end fraction, left parenthes...
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