Which equation is the inverse of y = 2x2 – 8?
- + x + 8
+VX+8
2
Oy=
NX
x = x +4
+II

A y =  ±sqrt((x+8)/2)

Step-by-step explanation:

y = 2x^2 -8

Exchange x and y

x = 2y^2 -8

Solve for y

Add 8 to each side

x+8 = 2y^2 -8+8

x+8 = 2y^2

Divide each side by 2

(x+8)/2 = 2y^2/2

(x+8)/2 = y^2

Take the square root of each side

±sqrt((x+8)/2) = sqrt(y^2)

±sqrt((x+8)/2) = y

First one

Step-by-step explanation:

y = 2x² - 8

y + 8 = 2x²

x² = (y + 8)2

x = +/- sqrt[(y + 8)/2]

For inverse, interswitch variables

f^-1(x) = +/- sqrt[(x + 8)/2]

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

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