Write an equation for a line that passes through the Irgun and perpendicular to y=5x-2

Well we have to find eq of line passing through origin and perpendicular to y=5x-2

First you need slope

As slope of y=5x-2 line is 5

So, slope of perpendicular line is -1/5

Also it passes through origin

as we know eq of line is y-y1=m(x-x1)

substitute X1,y1 = (0,0)

it becomes y =mx

so, y = -x/5

5y +x = 0 is required equation