A hemispherical tank is filled with water and has a diameter of 11 feet. If water weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank, to the nearest pound?

The total weight of the water in a full tank is 21744 pounds

Step-by-step explanation:

To solve the problem find the volume of the tank and multiply it by water weighs pounds per cubic foot to find the total weight of the water in a full tank

The formula of the volume of a sphere is V = πr³

∵ The tank is shaped a hemisphere

∵ The volume of a sphere = V = πr³

- Multiply it by one-half to find the volume of the hemisphere

∴ The volume of the tank = ( πr³)

∴ The volume of the tank =   πr³

∵ The hemisphere take has a diameter 11 feet

- The radius is one-half the diameter

∴ r = × 11 = 5.5 feet

- Substitute its value in the formula of the volume above

∵ The volume of the tank =   π(5.5)³  

∴ The volume of the tank = 348.4549852 feet³

Now lets find the total weight

∵ The water weighs 62.4 pounds per cubic foot

- Multiply the volume by 62.4

∴ The total weight of the water = 62.4 × 348.4549852

∴ The total weight of the water = 21743.59107

- Round it to the nearest pound (whole number)

∴ The total weight of the water = 21744 pounds

The total weight of the water in a full tank is 21744 pounds

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value