The length of a rectangle is six feet greater than the width. the perimeter is 168 feet. What are the dimensions of the rectangle?

45 feet by 39 feet

Step-by-step explanation:

l = length

w = width

Perimeter, p of a rectangle = 2( l + w)

and p = 168 feet

but l = 6 + w

substitute the value of l

168 = 2(( 6 + w) + w)

168 = 2( 6 + w +w)

168 = 2(6 + 2w)

expand

168 = 12 + 4w

subtract 12 from both sides

168 - 12 = 4w

156 = 4w

divide both sides by 4

39 = w

substitute the value of w in  l = 6 + w

l = 6 + 39

l = 45

Hence, the dimensions are 45 feet by 39 feet

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

his chances of getting a coin of higher value is 4/19

step-by-step explanation: