Point E has a negative x-coordinate, and its y-coordinate is not 0. Where could point E be located on the coordinate plane? Choose all answers that apply: (Choice A) Quadrant I (Choice B) Quadrant II (Choice C) Quadrant III (Choice D) Quadrant IV (Choice E) x-axis (Choice F) y-axis

B, C, and F.

Step-by-step explanation:

since there is a negative x-coordinate, it has to be on the left side of the coordinate plane. There are only 2 Quadrants on that side, Quadrant II, and quadrant III. It also said that the y-coordinate is not 0, so It cannot be on the x-axis becuase that would mean that the y-coordinate is 0, but it said nothing about the x-coordinate not being 0.

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.