Adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall. Using the empirical rule, approximately what percent of the adult male population is taller than the average basketball player?

Step-by-step explanation:

Mean = 70 inches

Standard deviation = 3 inches

Average basket ball player  = 79 inches

Since it is normally distributed assume with 5% significance .

So, it becomes,

At 0.05 level of significance , 0.0013 = 0.13% of the adult male population is taller than the average basketball player .

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2