After a reading group of foxes, F, were released into a protected area, it was determined that the population growth in T years follow the equation F(t)= 35.7/(0.25+(0.75^t)). F= The number of breeding foxes T= The number of years after the foxes were introduced (Only whole foxes, round down) set up a table at t=0. How many foxes, F, were there?. How many foxes Will there be in 2013 if the foxes were introduced in 2010? using the table and/ or graph what is the limiting value of y?

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

the expression (1.26)2t reveals the approximate rate of increases in the number of plants semiannually.

hope this : )

answer: sine

step-by-step explanation:

throw the computer

step-by-step explanation: