If a range hood removes contaminants at a flow rate of F liters of air per second, then the percent P of contaminants that are also removed from the surrounding air can be modeled by P=1.16F+31.23, where F is between and inclusive of 10 and 75. What flow rate F must a range hood have to remove 83% of the contaminants from the air?

answer: yes, he is correct

step-by-step explanation: 10x-1=59

                                              1-1=0     59+1=60

60/10=x=6

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09

answer: b)

step-by-step explanation:

its a dot plot because since the score is not high numbers.

- r3ktforgood ☕

step- i d k and i d c : )

you: : 0

bye