A square is changed into a new rectangle by increasing its width by 2 inches and decreasing its length by 2
inches. If the original square had a single length of 8 inches, find it's area and the area of the new rectangle. How many square inches larger is the square's area?

The area of the square is 64 square inches and the area of the new rectangle is 60 square inches. The square's area is 4 inches larger than the rectangle.

Step-by-step explanation: If a side length of the square measures 8 inches, then its area can be calculated as follows;

Area = L x W

The length and the width both measure 8 inches (all sides of a square are equal in length).

Area = 8 x 8

Area = 64

Also, the the new rectangle is formed by increasing the width of the square by 2 inches (that is 8 + 2 = 10), and decreasing the length by 2 inches (that is 8 - 2 = 6). The area of the new rectangle is calculated as follows;

Area = L x W

Area = 10 x 6

Area = 60

Therefore the area of the square is 64 square inches and the area of the rectangle is 60 square inches. The area of the square is 4 inches larger than that of the rectangle.

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