Mathematics, 09.04.2020 04:31 Kennethabrown09

Multiply. start fraction k plus 3 over 4 k minus 2 end fraction dot left parenthesis 12 k squared plus 2 k minus 4 right parenthesis

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Answer from: andersonemma2222

$\therefore \frac{(k+3)}{(4k-2)}.(12k^2+2k-4)=3k^2+11k+6$

Step-by-step explanation:

Factorization of a Quadratic polynomial:

In order to factorize ax^2+bx+c

we have to find out the numbers p and q such that, p+q = b and pq=ac.Finding the two integers p and q, we rewrite the middle term of the quadratic as px+qx. Then by grouping of the terms we can get desired factors.

Multiplication of two binomial:

(a+b)(c+d)

=a(c+d)+b(c+d)

=(ac+ad)+(bc+bd)

=ac+ad+bc+bd

Given that,

$\frac{(k+3)}{(4k-2)}.(12k^2+2k-4)$

$=\frac{(k+3)}{2(2k-1)}.2(6k^2+k-2)$ [ taking common 2]

$=\frac{(k+3)}{(2k-1)}.(6k^2+k-2)$ [ cancel 2]

$=\frac{(k+3)}{(2k-1)}.(6k^2+4k-3k-2)$

$=\frac{(k+3)}{(2k-1)}.\{2k(3k+2)-1(3k+2)\}$

$=\frac{(k+3)}{(2k-1)}.(3k+2)(2k-1)$

=(k+3).(3k+2)

=3k^2+9k+2k+6

=3k^2+11k+6

$\therefore \frac{(k+3)}{(4k-2)}.(12k^2+2k-4)=3k^2+11k+6$

Answer from: Quest

answer: e 9, 5.75

step-by-step explanation:

step 1

find the variation ab in the x coordinate

delta x=(x2-x1)=10-> 8 units

find the variation ab in the y coordinate

delta y=(y2-y1)=6-> 2 units

step 2

find the coordinates point c

x coordinate

cx=ax+delta x*2/> cx=2+8*(2/> cx=3

y coordinate

cy=ay+delta y*2/> cy=4+2*(2/> cy=4.25

the coordinates of point c are (3,4.25)

step 3

find the coordinates point d

x coordinate

dx=ax+delta x*4/> dx=2+8*(4/> dx=4

y coordinate

dy=ay+delta y*4/> dy=4+2*(4/> dy=4.5

the coordinates of point d are (4, 4.5)

step 4

find the coordinates point e

x coordinate

ex=ax+delta x*4/> ex=2+8*(6/> ex=5

y coordinate

ey=ay+delta y*4/> ey=4+2*(6/> ey=4.75

the coordinates of point e are (5, 4.75)

step 5

find the coordinates point f

x coordinate

fx=ax+delta x*4/> fx=2+8*(8/> fx=6

y coordinate

fy=ay+delta y*4/> fy=4+2*(8/> fy=5

the coordinates of point f are (6,5)

step 6

find the coordinates point g

x coordinate

gx=ax+delta x*4/> gx=2+8*(10/> gx=7

y coordinate

gy=ay+delta y*4/> gy=4+2*(10/> gy=5.25

the coordinates of point g are (7,5.25)

step 7

find the coordinates point h

x coordinate

hx=ax+delta x*4/> hx=2+8*(12/> hx=8

y coordinate

hy=ay+delta y*4/> hy=4+2*(12/> hy=5.5

the coordinates of point h are (8,5.5)

step 8

find the coordinates point i

x coordinate

ix=ax+delta x*4/> ix=2+8*(14/> ix=9

y coordinate

iy=ay+delta y*4/> iy=4+2*(14/> iy=5.75

the coordinates of point i are (9,5.75)

- r3ktforgood ☕

Answer from: Quest

hello from mrbilldoesmath!

answer: x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

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Multiply. start fraction k plus 3 over 4 k minus 2 end fraction dot left parenthesis 12 k squared pl...

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