Use the Intermediate Value Theorem to show that the polynomial f(x)=x^3+x^2-2x+19 has a real zero between -4 and -1.

Step-by-step explanation:

IVT --> If two points have a known y-value(one positive and one negative) and a known x-value, there has to be at least one real zero in between those two x-values. (assuming f(x) is continuous)

f(-4) = -64+16+8+19 = -21

f(-1) = -1+1+2+19 = 21

Conclusion: Since the -4 and -1 produce a postive y and negative y, there has to be atleast one zero in between.

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

£56

step-by-step explanation:

u divide 24 by 3 and u get 8 so if u do 8 time 7 or 8+8+8+8+8+8+8 u get 56 and 56 divided by 7 is 8.