A credit card bill for $559 was due on September 14. Purchases of $289 were made on September 19, and $15 was charged on September 28. A payment of $250 was made on September 25. The annual interest on the average daily balance is 19.5%. Find the finance charge due (in dollars) on the October 14 bill. (Use 365 for the number of days in a year. Enter a number. Round your answer to the nearest cent.)

$623

Step-by-step explanation:

calculation of Finance charge due on October 14

(+) $ 559 due on sep 14, $ 559 * (19.5*31) / (100 * 365) = $ 9.20

(+) purchase $ 289 on sep 19, $ 289 * (19.5*26 ) / (100 * 365) = $ 2.42

(+) finance charge on sep 28, $ 18 *(19.5*17 ) / (100 * 365) = $ 0.17

(-) Repayment on 25 sep , $ 250 * (19.5*20 ) / (100 * 365) = (2.745)

Total finance charges from 14 sep to 14 oct = $ 9.7= appr. 10

Amount due on 14 October = $559+$289+$15+$11.855- $250

= $ 623

the answer is 5636.7

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2