Find all the solutions of sin x + cos x = 1 in the interval [0, 2pie).

X = 0,  π/2 in the interval  [0, 2pi).

Step-by-step explanation:

Use the auxiliary angle method:

R sin(x + a)  = Rsin x cos a + Rcos x sin a = 1

                        sin x         +    cos x             = 1

Comparing coefficients:

R cos a = 1 and R sin a =  1, so

tan a = R sin a / R cos a  = 1

So a = π/4 radians.

Also  R^2(sin^2 a + cos^2 a) =  1^2 + 1^2 = 2

Therefore R = √2.

So √2 sin (x +π/4 = 1

sin x + π/4 = 1/√2

x  + π/4 = π/4

x = 0 radians

Also

x = 0 +  π/2 = π/2.

goog may be able to you find that answer

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: