Plz help derive ln(sinx)

cot(x)

Step-by-step explanation:

ln(sin(x)) = =

Step-by-step explanation:

I'm assuming you want to find the derivative of the function y = ln (sin x).

If this is the case, let's look at the derivatives of y = ln x and y = sin x separately and then use the results as appropriate:

(d/dx) ln x = 1/x

(d/dx) ln u = (1/u)(du/dx)

(d/dx) sin x = cos x

We'll also need to use the Chain Rule (which we have done in finding the derivative of ln u, above).

                                  1                                       1                        cos x

(d/dx) ln (sin x) = * (d/dx) (sin x) = * cos x = = cot x

                               sin x                                 sin x                      sin x

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

let y equal to

the total fare and x is the mile of taxi ride. so the equation is

y = 0.55x + 1.75

since susie has

$10 to spend for a taxi cab, so he can have

10 = 0.55x +

1.75

x = 15 miles of

taxi ride

so the system of

inequality is

10 < 0.55x +

1.75

x > 2