The perimeter of a rhombus is 40. What is the area of the square?

96 cm squared

Step-by-step explanation:

A rhombus has 4 edges of equal length. If it has perimeter of 40cm, then each length would be

40cm

 4           = 10cm

Divide the rhombus into 4 right-angle triangle by cutting along the 2 diagonals.

Each right-angle triangle will have a hypotenuse of 10cm and one other edge with length

12cm

2         =  6cm

Use Pythagoras Theorem to find the length of the remaining edge.

√(10cm) squared − (6cm) squared = 8cm

Now find the area of the triangle.

1

2 × 6cm ×8cm =24cm squared

Since the original rhombus was made up of four such triangles, the area of the rhombus would be

24cm squared × 4 = 96cm squared

the answer to the question is a

step-by-step explanation:

it has the same slope and the same y-intercept.

y + 11 = -7/9(x - 18)

y + 11 =-7/9x + 14

b

y = -7/9x + 3

y-intercept (0, 3)

150.6

all i did was i multiplied 5.02 by 30