You roll a die and pick a card of the two-card set with values 6 and 7. How many DIFFERENT sums are possible? Hint: list all with tree diagram and cross out repeated sums

The die is 1 2 3 4 5 or 6

The card is 6 or 7

Possible sums are

card=6)  1+6=7, 2+6=8, 3+6=9, 4+6=10, 5+6=11, 6+6=12,

card=7)   1+7=8, 2+7=9, 3+7=10, 4+7=11, 5+7=12, 6+7=13

We get seven different sums:  7 8 9 10 11 12 13

7

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

a

step-by-step explanation: