The airport has a moving walkway that moves at 2 feet per second. Suppose Calvin can travel 152
feet while walking on the walkway in the same amount of time it takes him to travel 72 feet while walking on the pavement without the aid of the moving sidewalk. How fast does Calvin walk by himself?

0.94 ft/sec

Step-by-step explanation:

Airport: 2 feet per second.

Total distance 152 ft in the same amount of time it takes him to talk 72 feet on the pavement.

152/2 = 76 - This is how many seconds he was walking in the airport.

He walked 76 seconds and moved 152 feet.

So that means if the SAME time was used so 76 seconds he walked 72 feet, then we can do 72ft/76sec to get 0.94ft/sec

5x+10 is the correct one

hope this

here is the

mark brainliest pl