The vertices of triangle ABC are A(5,2), B(-1,-6) and C(1,5). If Triangle DEF is similar to Triangle ABC and AB/DE=5, what could be the
coordinates of vertices D and E?

D(-42) and E(-4,-1)
D(-3,-1) and E(-1,1)
D(-5,3) and E(-5,1)
D(-2,-2) and E(2,0)

D(-5,3) and E(-5,1)

Step-by-step explanation:

|AB|² = (-1-5)² + (-6-2)²

|AB|² = 36 + 64

|AB|² = 100

|AB| = 10

AB/DE = 5

|DE| = 10/5 = 2

D(-5,3) and E(-5,1)

|DE|² = (-5+5)² + (3-1)²

|DE|² = 4

|DE| = 2

Verified

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90