You might need: Calculator Problem Suppose that Antonia rolls a pair of fair six-sided dice. Let AAA be the event that the first die lands on 555 and BBB be the event that the sum of the two dice is 666. Using the sample space of possible outcomes below, answer each of the following questions. What is P(A)P(A)P, (, A, ), the probability that the first die lands on 555

P(A)=1/6

Step-by-step explanation:

The sample space of the two dice is given below:

[1, 1], [1, 2], [1, 3], [1, 4], [1, 5], [1, 6]

[2, 1], [2, 2], [2, 3], [2, 4], [2, 5], [2, 6]

[3, 1], [3, 2], [3, 3], [3, 4], [3, 5], [3, 6]

[4, 1], [4, 2], [4, 3], [4, 4], [4, 5], [4, 6]

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

[6, 1], [6, 2], [6, 3], [6, 4], [6, 5], [6, 6]

n(S)=36

Let A be the event that the first die lands on 5

Sample Space of Event A is:

[5, 1], [5, 2], [5, 3], [5, 4], [5, 5], [5, 6]

n(A)=6

Therefore:

P(A)=n(A)/n(S)

=6/36

=1/6

saving = more money

step-by-step explanation:

if you have 100 bucks, and you want to buy a candy bar, even if you have one at home, if you choose not to buy it, you save.

~courtney

the best estimate is 3 because   8 can only go into 24 3 times