The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Approximate the change in total stopping distance as speed changes from x = 25 to x = 26 miles per hour.

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

We will approximate this distance  using the relation

dx = 26 - 25 = 1

T' =  2.5 + x

Therefore

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 ×

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = × 100

%  change in stopping distance = 7.34 %

answer: approximately 206 bones

i hope this u out a branlist and a would be greatly appreciated :

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an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this