Cara is playing a number game where she has two tiles for each number 0 to 9. A tile is chosen at random. How many favorable outcomes are there for choosing a multiple of 3?

Step-by-step explanation:

The number of possible numbers on the tile are:

0, 1 , 2 , 3 , 4,  5,  6,  7 ,  8 and 9.

Now, the chosen tile can have any of the ten options mentioned above.

The favorable outcomes are  3 , 6 and 9 as they are the multiple of 3.

So, the number of possible favorable outcomes  = 3 ways

Hence, if a card is chosen at random, there are 3 possible favorable outcomes for choosing a multiple of 3.

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!