The test statistic of zequals1.18 is obtained when testing the claim that pgreater than0.2. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of alphaequals0.05, should we reject Upper H 0 or should we fail to reject Upper H 0?

a) Right Tailed

b) p-value = 0.119

c) We fail to reject the Null Hypothesis()

Step-by-step explanation:

We have the following data:

Test Statistic = z = 1.18

Claim: p > 0.2

Part a) Type of Test

Remember that when there is Greater than, Lesser than or any synonymous word in the claim, this means that the test is one-tailed.

Since, the claim is that p is greater than 0.2, the hypothesis test will be Right Tailed.

Part b) P-value

We have to find the p-value for the given test statistic. Since, the test statistic is a z-value we will use z-table to find the p-value for this score. Since, this z-score is for claim that p is greater than 0.2, so we will find the p-value(probability) of score being above 1.18

The p-value of z being greater than 1.18 comes out to be 0.119. i.e.

p-value = 0.119

Part c) Decision

Calculated p-value is 0.119 and significance level = 0.05. The rule is:

Since, in this case our p-value is greater than the significance level, we fail to reject the null hypothesis ().

step-by-step explanation:

se a cavasery6

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0