Let X be a binomial random variable with n = 9 and p = 0.2 (nine trials, probability of success = 0.2). Find the probability of 4 successes, i. e., P(X = 4). Give your answer as a decimal to three decimal places, e. g., 0.123. Round as needed.

The probability of 4 successes,

P(X=4) =0.0660

Step-by-step explanation:

Step 1:-

Let X be a binomial random variable with n = 9 and p = 0.2

probability of successes p = 0.2

probability of failure q = 1-p = 1-0.2 = 0.8

By using binomial distribution

Step 2:-

The probability of 4 successes, i.e.,

by using

P(X=4) =0.0660

conclusion:-

The probability of 4 successes, that is P(X=4) =0.0660

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step-by-step explanation: