Mathematics, 07.04.2020 22:17 heavenwagner

Express the confidence interval (0.069 comma 0.121 )in the form of ModifyingAbove p with caret minus Upper E less than p less than ModifyingAbove p with caret plus Upper E.

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Answer from: stodd9503

For this case the confidence interval is given by: (0.069, 0.121)

And we can estimate the sample proportion like this:

$\hat p = \frac{0.069+0.121}{2}= 0.095$

And the margin of error given by: $ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ can be calculated with this formula:

ME= 0.121-0.095 = 0.026

ME= 0.095 -0.069 = 0.026

And for this case we can express the interval like this:

$0.095 \pm 0.026$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

For this case the confidence interval is given by: (0.069, 0.121)

And we can estimate the sample proportion like this:

$\hat p = \frac{0.069+0.121}{2}= 0.095$

And the margin of error given by: $ME= z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ can be calculated with this formula:

ME= 0.121-0.095 = 0.026

ME= 0.095 -0.069 = 0.026

And for this case we can express the interval like this:

$0.095 \pm 0.026$

Answer from: Quest

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

Answer from: Quest

1.true 2.false? ? i think. .

step-by-step explanation:

Can somebody me ? im being timed, and i just need the main answer to this , you can explain if you

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