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The dimensions of a chocolate box are: height = x+2 inches, length = 2x+5 inches, and width = 4x-1 inches. if the volume of the box is 605 cubic inches, what is the value of x?

I'm a bit stuck on this, so any help is appreciated. The work I have is:

(2x+5)*(4x-1)*(x+2) = 605

(8x^2 + 20x – 2x – 5) * (x + 2)

(8x^3 + 20x^2 – 2x^2 – 5x) + (16x^2 + 40x – 4x – 10)

Regroup

8x^3 + (20x^2 – 2x^2 + 16x^2) + (40x – 5x – 4x) – 10

8x^3 + 34x^2 + 31x – 10 = 605

+10 +10

8x^3 + 34x^2 + 31x = 615

42x^5 + 31x = 615

73x^6 = 615

But I'm not exactly sure about it.

This is my second time asking this.

x= 3 inches

Step-by-step explanation:

-The volume of a box is given by the formula:

-We are given the dimensions h=x+2, l=2x+5 and w=4x-1.

We substitute this values in the formula and equate to the volume value.

#We take the values to the same side and equate to zero;

#Applying the zero factor principal to obtain the different values of x:

#We use the quadratic formula to solve the two other values of x:

The two other values are negatives. Ignore them since length cannot be a negative.

The only reasonable value of x is x=3

#We substitute in the formula to validate:

Hence, the value of x is 3 inches

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet