An animal shelter spends $5.50 per day to care for each cat and $7.00 per day to care for each dog. Ryan noticed that the shelter spent $52.50 caring for cats and dogs on Monday. Ryan found a record showing that there were a total of 9 cats and dogs on Monday. How many cats were at the shelter on Monday?

There were 7 cats

Step-by-step explanation:

In this question, we are asked to calculate the number of individual cats and dogs present at an animal shelter on a certain Monday.

Since we do not know the exact numbers, let’s represent these animals by variables. Let the number of dogs be d and the number of cats be c .

Since there are a total of 9 animals, this means;

c + d = 9 •••••••••(I)

Let’s now get the second equation out of their finances;

Total amount spent on dogs will be 7 * d = 7d while total amount spent on cats will be 5.5 * c = 5.5c. If we add both, we will get the total amount spent which is $52.5

Mathematically therefore;

5.5c + 7d = 52.5 ••••••••(ii)

Now from 1, we can say that c = 9 - d

Let’s substitute this in ii

5.5(9-d) + 7d = 52.5

49.5 - 5.5d + 7d = 52.5

1.5d = 52.5 - 49.5

1.5d = 3

d = 3/1.5 = 2

Since d = 2, c = 9 - d = 9 - 2 = 7

There were 7 cats at the shelter on Monday.

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations using the information given.

Isolating d on the first equation:

d =9 -c

Replacing the value of d in the second equation

5.50 c + 7 d = 52.50

5.50 c + 7 (9-c) = 52.50

5.50c +7(9) -7(c) =52.50

5.50c +63 -7c =52.50

63 -52.50 = 7c-5.50c

10.5= 1.5c

10.5/1.5=c

c= 7

There were 7 cats at the shelter on Monday.

Feel free to ask for more if needed or if you did not understand something.

the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube