The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section 4.2, y2 = y1(x) e−∫P(x) dx y 2 1 (x) dx (5) as instructed, to find a second solution y2(x). y'' − 4y' + 4y = 0; y1 = e2x

The general solution is

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and

To find the we are applying the following formula,

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

The general solution is

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap