For fixed positive integers m and n, the set Upper M Subscript m times n of all mtimesn matrices is a vector space, under the usual operations of addition of matrices and multiplication by real scalars. Let F be a fixed 3times2 matrix, and let H be the set of all matrices A in Upper M Subscript 2 times 4 with the property that FAequals0 (the zero matrix in Upper M Subscript 3 times 4). Determine if H is a subspace of Upper M Subscript 2 times 4.

Yes, H is a subspace

Step-by-step explanation:

Recall that given a vector space V, a subset W of V is a subspace if and only if

- the 0 of V is in W

- given a, b in W, then a+b is in W

- given a real scalar r and a in W, then ra is in W.

In order to see if H is a subspace of we must check the three properties.

- It is clear that the matrix 0 in   is in H since (where the right hand 0 is the 0 vector in .

- Let A,B in H. We want to check that A+B is in H. Since A,B in H we have that FA=0 and FB=0. We have that

Then A+B is in H.

- given a real number r, and a matrix A in H, we want to check if rA is in H. Then

which shows that rA is in H.

Hence, H is a subspace of

sgth thdhtxr ythdsx hfgh ysrth th srtrh

step-by-step explanation:

trshd h rdhsjsdrnytjdt jyjyukfddythj

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐