Which test point holds true for the inequality 3/2-2x>1

2/3 x - 2y ≥ 1⇒ y≤ 1/3 x -1/2

(1,6) holds false for the inequality

(2,3) false

(3,2) false

(6,1) holds true for the inequality

The solution (shaded area) lies below the boundary line, which is y = 1/3 x -1/2

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.