What are the coordinates of the vertex of the function f(x)=x^2+10x-3

(-5,-28)

Step-by-step explanation:

f(x)=x^2+10x-3

Axis of symmetry is -b/2a.

-10/2 = -5. This is the x value of the vertex.

Plug in to solve for y.

-5^2+10(-5)-3 = -28.

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

step-by-step explanation:

for the free