Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

Step-by-step explanation:

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

So , Let's calculate how many terms are there as :

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Sum of an AP is :

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Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

The sum of the given sequence is -25500.

Step-by-step explanation:

The given Arithmetic sequence is 46 + 42 +38... +(-446) +(-450).

To find the number of terms in the sequence :

The formula used is

where,

Therefore,

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∴ The number of terms, n = 125.

To find the sum of the arithmetic progression :

The formula used is

where,

Therefore,

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∴ The sum of the given sequence is -25500.

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1