If f (1) =4 and f(4)= f (n-1)-4 then find the value of f(4)

f(1) = 4 is given

f(n) = f(n-1)-4 is the recursive step or rule

f(2) = f(2-1)-4 ... replace n with 2

f(2) = f(1) - 4

f(2) = 4-4 ... replace f(1) with 4

f(2) = 0

Repeat for n = 3

f(n) = f(n-1)-4

f(3) = f(3-1)-4

f(3) = f(2) - 4

f(3) = 0 - 4 replace f(2) with 0, which is from f(2) = 0 found earlier

f(3) = -4

Repeat for n = 4

f(n) = f(n-1)-4

f(4) = f(4-1)-4

f(4) = f(3) - 4

f(4) = -4-4 ... plug in f(3) = -4

f(4) = -8

y=mx+b

step-by-step explanation:

m slope

b y-intercept

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.