The circumference of ruby's old swimming pool is 47.1 feet. Her new swimming pool has a diameter of 21 feet. How much larger is the new swimming pools circumference?

The new pool is 18.84 feet larger in circumference than the old one.

Explanation:

Given:

Circumference of the pool = 47.1 feet

Diameter of the new pool, d = 21 feet

radius, r = 21/2 feet

Circumference of the new pool = ?

We know:

Circumference = 2πr

where,

r is the radius

On substituting the value:

C =

C = 65.94 feet

The difference in circumference of the two pools = 65.94 - 47.1 feet

                                                                                  = 18.84 feet

Therefore, the new pool is 18.84 feet larger in circumference than the old one.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068