The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probability of the following events.

a. No accidents occur in one week.
b. 5 or more accidents occur in a week.
c. One accident occurs today.

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

Formula:

a) No accidents occur in one week.

b) 5 or more accidents occur in a week.

c) One accident occurs today.

The mean number of accidents per day is given by

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

$20.01

step-by-step explanation:

the sale price is (1.00 - 0.77)($87), or 0.23($87), or $20.01.