A toy rocket launched into the air has a height (h feet) at any given time (t seconds) as
h = -16t2 + 160t until it hits the ground. At what time(s) is it at a height of 9 feet above the
ground?

t =0.06s and t=9.94 s

Step-by-step explanation:

The equation that models the height of the rocket is

when the rocket is at height of 9 fret above the ground, then

This implies that:

Rewrite in standard quadratic form.

The solution is given by

The rocket reach the height of 9 feet at times t=0.06s and t=9.94 seconds

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: