If 62.7 g n2 react with 23.8 g h2 according to the reaction below, how many grams of ammonia (nh3) can be produced, and how many grams of the excess reactant will be left over?

unbalanced equation: n2 + h2 → nh3

10.3648 g of hydrogen gas will be left over.

Step-by-step explanation:

Balanced chemical equation:

Moles of nitrogen gas =

Moles of hydrogen gas =

According to reaction 1 mol of nitrogen gas reacts with 3 mol of hydrogen gas.Then 2.2392 moles of nitrogen gas will react with:

of hydrogen

Mass of 6.7176 moles of hydrogen gas = 6.7176 mol × 2 g/mol = 13.4352 g

Nitrogen gas is in limited amount which will limit the formation of ammonia gas.

Mass of hydrogen gas left unreacted = 23.8 g - 13.4352 g=10.3648 g

10.3648 g of hydrogen gas will be left over.

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: