I need help on 2 column proofs!!

The proof is given below.

Step-by-step explanation:

Given,

AB║DC and AB≅DC

To proof ΔABE ≅ Δ CDE

Proof:

AB║DC and AC is the transversal

∠BAE = ∠ECD ( alternate angle)

AB║DC and BD is the transversal

∠ABE = ∠EDC( alternate angle)

Now,

In ΔABE and Δ CDE

∠BAE = ∠ECD ( alternate angle)

∠ABE = ∠EDC( alternate angle)

∠AEB = ∠CED (vertically opposite angle)

So, by AAA condition we get,

ΔABE ≅ Δ CDE

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w