Acatapult launches a boulder with an upward velocity of 112 ft/s. the height of the boulder, h, in feet after t seconds is given by the function .
how long does it take the boulder to reach its maximum height? what is the boulder’s maximum height? round to the nearest hundredth, if necessary. h=-16t^2+112t+30
a. 7 s; 30 ft
b. 3.5 s; 366 ft
c. 3.5 s; 618 ft
d. 3.5 s; 226 ft

To determine the time it takes for boulder to reach its maximum height, derive the equation and equate to zero.
                                 h = -16t² + 112t + 30
                   dh / dt = 0 = -32t + 112
The value of t from the equation above is 3.5 s. Substitute this value of t to the original question, 
                                 h = -16(3.5 s)² + 112(3.5 s) + 30 = 226 ft
Thus, the answer is letter D. 

The answer for this is 9/1253decimal form 0.007