How much of a 30% solution do you need to add to 280 ml of water to obtain a 4% solution? Need to set up 2 equations with two variables each to find x and y
The hints given are:
x=the amount of ml's needed to be added to the 280 mls and
y= the amount of the 30% solution that is contained in the amount added to the 280 mls

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

p

step-by-step explanation: