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(1+1+1)!=6

2+2+2=6

(3×(3/3)!=6

(4-(4/4))!=6

5+(5/5)=6

6*(6/6)=6

7-(7/7)=6

((∛8)+(8/8))!=6

(√9×(9/9))!=6

Step-by-step explanation:

Since no restrictions were given on what operations to use the factorial operation is just n!=n×(n-1)×(n-2)...1:

These are the arithmetic steps:

(1+1+1)!=3!=3×2=6

2+2+2=6

(3×(3/3))!=3!=3×2=6

(4-(4/4))!=(4-1)!=3!=3×2=6

5+(5/5)=5+1=6

6*(6/6)=6*1=6

7-(7/7)=7-1=6

((∛8)+(8/8))!=(2+1)!=3!=3×2

(√9×(9/9))!=(3×1)!=3×2=6

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2