If p(x)=x^3-3x^2-x+3 and p(3)=0, what is a factor of p(x)

Since p(3) = 0, this means x = 3 plugs into p(x) to get 0

We can write p(x) as p(x) = (x-3)q(x) where q(x) is some other polynomial that multiplies with (x-3) to lead to x^3-3x^2-x+3

Let's plug in x = 3 and see what happens

p(x) = (x-3)q(x)

p(3) = (3-3)q(3)

p(3) = 0*q(3)

p(3) = 0

No matter what the result of q(3) was, it doesn't matter because it multiplies with 0 to get 0.

The general rule is: if p(k) = 0, then x-k is a factor of p(x). This is a special case of the remainder theorem.

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