Calculators are sold to students for 20 dollars each. Three hundred students are willing to buy them at that price. For every 5 dollar increase in price, there are 30 fewer students willing to buy the calculator. Let x the number of times the price is increased and let R stand for revenue.

At the maximum revenue, the actual selling price will be $
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The answer is $35.

Step-by-step explanation:

If you do the process, you will get $35. First, put in the calculator 20 x 300 to get 6000. Now for each time after this, add five dollars to the price of the calculators and subtract 30 students from the total number of students. You will notice that any price after $35 decreases from a revenue of $7,350. So therefore, the answer is $35.

im guessing (23,14). hope this : )